## What number should be subtracted from both 31 and 40 so that their third proportional is 5 more than 43?

A. 1
B. 2
C. 4
D. 13

### Solution

Let the number subtracted be T.

⇒ Third proportional of (31-T) and (40-T) is 5 more than 43.

⇒ (31 – T)/(40 – T) = (40 – T)/48

⇒ 1488 – 48T = 1600 + T2 – 80T

⇒ T2 – 32T + 112 = 0

⇒ (T – 28)(T – 4) = 0

∴ T can be either 28 or 4, but among the options only option 4 is given. So, 4 must be subtracted from both 31 and 40 so that their third proportional is 5 more than 43.

A. 20 km/hr
B. 48 km/hr
C. 50 km/hr
D. 60 km/hr

## In a school, 10% of the boys are same in number as 1/4 of the girls. What is the ratio of boys to girls in that school?

A. 3:2
B. 2:1
C. 4:3
D. 5:2

### Solution

Ratio Of Boys : Girls= (1/4) : (10/100)    [As,10%=10/100)]

= 5:2

## 1/4 of Arif’s income and 1/3 of Babu’s income equal Tk. 1100.If 1/8 of Arif’s income is equal to 1/5 of babu’s income,what is Babu’s income?

A. 1100
B. 1200
C. 1400
D. 1500

### Solution

Ratio Of A:B=1/(1/8): 1/(1/5)=8:5

Now,1100 Tk. =((8x(1/4)+5x(1/3)) Part =11/3 part

Now,11/3 part =1100 Tk (According to the Question)
Then, B= 5 part= 1100x (3/11)x5=1500 Tk

## Father’s present age is 50 yrs. His age was equal to his son’s present age at the time of the son’s birth. What was son’s age 10 yrs. ago?

A. 12
B. 15
C. 20
D. 25

Let the son’s present age be x years.
From the given data, it is known that
Father’s age at the time of son’s birth = Son’s present age
∴ 50 – x =x
⇒ 50 = 2x
⇒ x = 25
∴ son’s age 10 yrs ago = (25 – 10) = 15 yrs.

## Analogy: Underscore: Emphasis

B. Stigmatize: Confrontation
C. Quantify: Assessment
D. Brand: Ownership

## Analogy: GOVERNMENT: TAX

A. Student: Fees
B. Orange: Price
C. Company: Profit
D. Chairman: Parliament

## Analogy: Just: Arbitrary

A. Order: Chaos
B. Bare: Clothed
C. Hope: Surprise
D. Proper: Improper

## Idiom : Happy camper

A. Do something before it’s time to do it
B. A person who is content or satisfied
C. A big disappointment
D. To give someone credit or praise