## The sum of the series 1, 5,9,13 ____ to 40th series is:

A. 153

B. 158

C. 3160

D. None of these

### Answer

Correct Answer: **C. 3160**

### Solution

The given series is an arithmetic progression with the first term (a) being 1 and the common difference (d) being 4.

To find the sum of the series up to the 40th term, we can use the formula for the sum of an arithmetic progression:

S = (n/2) x [2a + (n-1)d]

where S is the sum of the series, n is the number of terms in the series, a is the first term, and d is a common difference.

Substituting the values into the formula, we get:

S = (40/2) x [2(1) + (40-1)(4)] S = 20 x [2 + 39(4)] S = 20 x 158 S = 3,160

Therefore, the sum of the series 1, 5, 9, 13, …, up to the 40th term is 3,160.