## Find the amount on Rs.5000 in 2 years, the rate of interest being 4% per first year and 5% for the second year?

A. Rs.460

B. Rs.5640

C. Rs.5460

D. Rs.5604

### Answer

Correct Answer: **C. Rs.5460 **

Skip to content
**
**
# Category: Compound Interest MCQs

## Find the amount on Rs.5000 in 2 years, the rate of interest being 4% per first year and 5% for the second year?

### Answer

## What amount does Kiran get if he invests Rs.8000 at 10% p.a. compound interest for two years, compounding done annually?

### Answer

### Detail About MCQs

## The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned.

### Answer

### Detail About MCQs

## Find the compound interest accrued on an amount of Rs.14,800 at 13.5% p.a at the end of two years. (Round off your answer to nearest integer)

### Answer

### Detail About MCQs

## Jameel invested an amount of Rs.17400 for two years. Find the rate of compound interest that will fetch him an amount of Rs.1783.50 at the end of two years?

### Answer

### Detail About MCQs

## Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest?

### Answer

### Detail About MCQs

## A sum of Rs.4800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.

### Answer

### Detail About MCQs

## A man gets a simple interest of Rs.500 on a certain principal at the rate of 5% p.a in two years. Find the compound interest the man will get on twice the principal in two years at the same rate.

### Answer

### Detail About MCQs

## The simple interest accrued on an amount of Rs.49500 at he end of three is Rs.17820. What would be the compound interest accured on the same amount at teh same rate in the same period? (Round off your answer to two decimal places)

### Answer

### Detail About MCQs

## The compound interest accrued on an amount of Rs.44000 at the end of two years is Rs.1193.60. What would be the simple interest accrued on the same amount at the same rate in the same period?

### Answer

### Detail About MCQs

A. Rs.460

B. Rs.5640

C. Rs.5460

D. Rs.5604

Correct Answer: **C. Rs.5460 **

A. Rs.9630

B. Rs.9680

C. Rs.9610

D. None of these

Correct Answer: **B. Rs.9680**** **

A= P{1 + R/100}^{n}

=> 8000{1 + 10/100}^{2}^{2} = Rs.9680

A. Rs.18,828.80

B. Rs.19,828.80

C. Rs.18,028.80

D. Rs.17,828.80

Correct Answer: **B. Rs.19,828.80 **

Let the sum be Rs.P

P{ [ 1 + 8/100]^{2} – 1 } = 2828.80

P(8/100)(2 + 8/100) = 2828.80 [a^{2} – b^{2} = (a – b) ( a + b)] P = 2828.80 / (0.08)(2.08) = 1360/0.08 = 17000 Principal + Interest = Rs. 19828.80

A. Rs.4273

B. Rs.4613

C. Rs.4064

D. Rs.4266

Correct Answer: **D. Rs.4266 **

CI = 14800{ [ 1 + 13.5/100]^{2} – 1 }

= 14800 { [1 + 27/200]^{2} – 1

= 14800 { 2 + 27/200}{27/200}

= (74)[2 + 27/200](27) =

1998[2 + 27/200] = 3996 + 269.73 = Rs. 4266

A. 8% p.a

B. 6% p.a

C. 4% p.a

D. 5% p.a

Correct Answer: **D. 5% p.a **

Let the rate of interest be R% p.a.

17400[1 + R/100]^{2} = 17400 + 1783.50

[1 + R/100]^{2} = (17400 + 1783.50)/17400

= 1 + 1025/10000 = 1 + 41/400

= 441/400 = [21/20]^{2}

[1 + R/100] = 21/20

R/100 = 1/20

Therefore R = 5

A. 18% p.a

B. 22% p.a

C. 20% p.a

D. 24% p.a

Correct Answer: **C. 20% p.a **

Rs.1440 – 1200 = Rs.240 is the interest on Rs.1200 for one year.

Rate of interest = (100 * 240) / (100 * 1) = 20% p.a

A. Rs.2520

B. Rs.3120

C. Rs.3320

D. Rs.2760

Correct Answer: **B. Rs.3120 **

Let A be the amount received at the end of the three years.

A = 4800[1 + 10/100][1 + 20/100][1 + 25/100]

A = (4800 * 11 * 6 * 5)/(10 * 5 * 4)

A = Rs.7920

So the interest = 7920 – 4800 = Rs.3120

A. Rs.500

B. Rs.250

C. Rs.5012.50

D. None of these

Correct Answer: **D. None of these **

Let the principal be Rs.P

S.I at 5% p.a in 8 years on Rs.P = Rs.500

(P)(8)(5)/100 = 500

P = 1250

C.I on Rs.2P i.e., Rs.2500 at 5% p.a in two years

= 2500{ [1 + 5/100]^{2} – 1} = 2500{ 21^{2} – 20^{2} /20^{2}}

= 2500/400(441 – 400)

= 25/4(41) = 1025/4 = Rs.256.25

A. Rs.20043.94

B. Rs.18654.81

C. Rs.20264.46

D. Rs.19612.41

Correct Answer: **A. Rs.20043.94 **

Let the rate of interest be R% p.a.

(49500)(3)(R)/100 = 17820

495R = 5940

R = 12

CI on Rs.49500 at 12% p.a. for three years

= 49500{[1 + 12/100]^{3} – 1} = 69543.936 – 49500 = Rs.20043.94

when rounded off to two decimal places.

A. Rs.10,840

B. Rs.10,720

C. Rs.10,560

D. Rs.10,280

Correct Answer: **C. Rs.10,560 **

Let the rate of interest be R% p.a.

4400{[1 + R/100]^{2} – 1} = 11193.60

[1 + R/100]^{2} = (44000 + 11193.60)/44000

[1 + R/100]^{2} = 1 + 2544/1000 = 1 + 159/625

[1 + R/100]^{2} = 784/625 = (28/25)^{2}

1 + R/100 = 28/25

R/100 = 3/25

Therefore R = 12 SI on Rs.44000 at 12% p.a. for two years = 44000(2)(12)/100

=Rs.10560